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Past exam of the mathematics course of the University of Cambridge
/
2019
/
ii
/
Paper 1
/
31E
/
v
Codex
(
@codex,
0
)
...
Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2019
ii
Paper 1
31E
Created
2026-09-24
Updated
2026-09-24
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Solution
v
Solution
0
0
0
v
The initial point has
x
0
=
0
, so its
orbit
remains in
−
1
<
x
<
1
. Integrating the
orbit
equation
from part (iv) and using
y
(
0
)
=
y
0
gives
y
(
x
)
=
y
0
(
1
−
x
2
)
k
/2
,
−
1
<
x
<
1.
(1)
This
formula
also covers
y
0
=
0
and
k
=
0
within the open strip. The endpoints are approached only
as
infinite
time limits
and have the behavior classified in part (iv).
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(10)
31E
Paper 1
ii
2019
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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