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Past exam of the mathematics course of the University of Cambridge / 2019 / ii / Paper 1 / 31E / v / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2019 ii Paper 1 31E v
Created 2026-09-24 Updated 2026-09-29  0 By others on same topic  0 Discussions Create my own version
The initial point has x0​=0, so its orbit remains in −1<x<1. Integrating the orbit equation from part (iv) and using y(0)=y0​ gives
y(x)=y0​(1−x2)k/2,−1<x<1.​
(1)
This formula also covers y0​=0 and k=0 within the open strip. The endpoints are approached only as infinite time limits and have the behavior classified in part (iv).

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