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Past exam of the mathematics course of the University of Cambridge / 2019 / iii / Paper 310 / 2 / b / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Cambridge 2019 iii Paper 310 2 b
Created 2026-10-03 Updated 2026-10-20  0 By others on same topic  0 Discussions Create my own version
The reaction maintaining chemical equilibrium is
e−+e+↔γ+γ​.
(1)
For T<me​ and negligible chemical potentials, the electron and Positron are dilute and obey the nonrelativistic equilibrium number density. Including two spin states for each particle,
ne−​+ne+​=4(2πme​T​)3/2e−me​/T.
(2)
The photon number density is nγ​=2ζ(3)T3/π2, so the electron-positron equilibrium pair abundance below the electron mass is
nγ​ne−​+ne+​​=ζ(3)2π2​(2πTme​​)3/2e−me​/T​.
(3)
If ne​ denotes only one of the charge-conjugate species, this expression is divided by two.

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