Choose a bijection , and conjugate the translation of the integers:
Then is a bijection of . Its th iterate is , which has no fixed point for every . Hence .
The set is uncountable. Partition into countably many infinite sets , and choose bijections . For every subset , define a permutation separately on each block by
Every positive iterate translates each integer coordinate by a nonzero amount, so it has no fixed point and . Distinct subsets give distinct permutations, yielding an injection . Since the power set is uncountable,
In fact its cardinality is the continuum, because it is a subset of all functions .

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