For subgroups and an -representation , Mackey restriction formula is
Frobenius reciprocity states
Applying these with gives
The identity double coset contributes one exactly when is irreducible, and every summand is a nonnegative integer. This proves Mackey irreducibility criterion: the induced representation is irreducible exactly when is irreducible and every nonidentity double-coset summand vanishes.
Now take , , and . Then
the subgroup fixing both and . Conjugation by fixes every element of this subgroup, so the two representations appearing in the corresponding Mackey summand are both . Their inner product is positive because this restriction is nonzero. Hence the Mackey irreducibility criterion fails whenever is irreducible. If is reducible, induction preserves its direct-sum decomposition, so the induced representation is again reducible. Therefore is never irreducible for .

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