If the germ of a sheaf section is zero, then by the definition of a stalk of a sheaf there is a neighbourhood of on which . Every point of also has zero germ. Thus the complement of is open, so the support of a sheaf section is closed.
The kernel of the restriction mapconsists exactly of sections whose germs vanish outside , namely . This proves exactness. If is a flasque sheaf, the restriction map is surjective by definition.
Now let be exact. The global section functor is left exact, so a section of mapping to zero lifts uniquely to a global section of . Its germs outside vanish because is injective at each stalk of a sheaf. It therefore lies in , proving exactness of the supported-section sequence.
Suppose in addition that is flasque and take . Surjectivity on global sections gives a lift . On , its restriction comes from some by left exactness. Extend to using flasqueness. Then maps to and vanishes outside , proving surjectivity on the right.
Write , , and . Since is an integral domain, no nonzero global section is supported only at the origin, soThe punctured affine plane has the affine cover . Its Čech cochain complex for the structure sheaf isConsequently
Because is affine, the higher sheaf cohomology of vanishes. The long exact sequence for local cohomology therefore givesand for . The nonzero group has the -basisThis computes the local cohomology of the affine plane supported at the origin in every degree.
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