The integral of an exact differential form over the closed curve is zero by Stokes theorem, so the map is well defined on de Rham cohomology. It is surjective because the angular form has integral . If a closed one-form has zero integral, define
The zero period makes this definition -periodic, and . Thus the kernel is zero and
is an isomorphism.
The overlap is in the coordinate , and radial projection is a deformation retraction onto . The homotopy invariance of de Rham cohomology identifies its first de Rham cohomology with that of , and the identification is compatible with integration around the unit circle. Hence the same integral map is an isomorphism.
Each is isomorphic to and is therefore contractible. Every complex line bundle over a contractible paracompact space is trivial, so and admit the required trivializations.
Since ,
The fundamental theorem of calculus and the chain rule then give
Thus is constant.
Parametrize the unit circle by a loop . Part (d) and imply
The kernel of the complex exponential function is , so
for some . This integer is the winding number of .
For ,
The scalar-valued form is closed, and
By the period isomorphism from part (b), in complexified de Rham cohomology. Hence there is a smooth complex-valued function on with .
Using ,
The overlap is connected, so for some . Choose with and replace by . Then .
Let be a smooth partition of unity subordinate to . On , extend by zero away from the overlap, and on extend similarly. Define
On the overlap,
and therefore
Changing the two local frames by the nowhere-zero functions replaces the transition function by
With the standard convention that the tautological bundle has transition function , its th tensor power has transition function . Thus
This is the smooth classification of complex line bundles on the complex projective line by their winding number.

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