The integral of an exact differential form over the closed curve is zero by Stokes theorem, so the map is well defined on de Rham cohomology. It is surjective because the angular form has integral . If a closed one-form has zero integral, defineThe zero period makes this definition -periodic, and . Thus the kernel is zero andis an isomorphism.
The overlap is in the coordinate , and radial projection is a deformation retraction onto . The homotopy invariance of de Rham cohomology identifies its first de Rham cohomology with that of , and the identification is compatible with integration around the unit circle. Hence the same integral map is an isomorphism.
Each is isomorphic to and is therefore contractible. Every complex line bundle over a contractible paracompact space is trivial, so and admit the required trivializations.
Parametrize the unit circle by a loop . Part (d) and implyThe kernel of the complex exponential function is , sofor some . This integer is the winding number of .
For ,The scalar-valued form is closed, andBy the period isomorphism from part (b), in complexified de Rham cohomology. Hence there is a smooth complex-valued function on with .
Let be a smooth partition of unity subordinate to . On , extend by zero away from the overlap, and on extend similarly. DefineOn the overlap,and therefore
Changing the two local frames by the nowhere-zero functions replaces the transition function byWith the standard convention that the tautological bundle has transition function , its th tensor power has transition function . ThusThis is the smooth classification of complex line bundles on the complex projective line by their winding number.
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