For and , the scalar product is the inner product
The cross product is
It is perpendicular to both vectors and has magnitude .
The vector triple product identity gives
Applying the same identity after reversing the outer cross product gives
The formulas differ because the cross product is not associative.
Let
Linear independence implies that the scalar triple product is nonzero. Applying the vector triple-product formulas to recovers the coefficients of in the basis . Equivalently, the reciprocal basis to is
Taking scalar products with therefore yields
Because the sphere passes through the origin and has centre , its radius is . A point lies on it exactly when
or equivalently
With , the three required equations are the Gram matrix system
For the specified vectors this becomes
Thus
and the centre is

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