For and , the scalar product is the inner productThe cross product isIt is perpendicular to both vectors and has magnitude .
The vector triple product identity givesApplying the same identity after reversing the outer cross product givesThe formulas differ because the cross product is not associative.
LetLinear independence implies that the scalar triple product is nonzero. Applying the vector triple-product formulas to recovers the coefficients of in the basis . Equivalently, the reciprocal basis to isTaking scalar products with therefore yields
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