This is the affine plane through , provided and are independent. The scalars are affine coordinates in those two directions.
The cross product of the plane normals is proportional to , soThe point on the intersection perpendicular to iswhich satisfies both plane equations and . Hence the line is .
The signed displacement of the sphere centre from the plane is . Orthogonal projection gives the circle centrePythagoras givesA real circle exists when : equality gives tangency and radius zero, while strict inequality gives a genuine circle.
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