This is the plane through perpendicular to the nonzero normal vector .
This is the affine plane through , provided and are independent. The scalars are affine coordinates in those two directions.
This is the sphere with centre and radius .
The cross product of the plane normals is proportional to , so
The point on the intersection perpendicular to is
which satisfies both plane equations and . Hence the line is .
The equally inclined line has direction . The distance between the two skew lines is
The signed displacement of the sphere centre from the plane is . Orthogonal projection gives the circle centre
Pythagoras gives
A real circle exists when : equality gives tangency and radius zero, while strict inequality gives a genuine circle.

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