Yes. The states and are orthogonal, since
A joint projective measurement in the Bell basis therefore distinguishes them with certainty. Concretely, a controlled-NOT followed by a Hadamard gate converts the Bell basis into the computational basis before measurement.
No. Taking the partial trace over gives
Every measurement on alone therefore has identical outcome probabilities in the two cases. This is the local indistinguishability of Bell-state phase.
Yes. Alice and Bob both measure in the Hadamard basis . The identities
show that their outcomes agree for and differ for . After exchanging one classical bit they know which state they had. This is the LOCC discrimination of two Bell states.

Articles by others on the same topic (0)

There are currently no matching articles.