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Past exam of the mathematics course of the University of Cambridge
/
2024
/
ib
/
Paper 1
/
17A
(Numerical Analysis)
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Course of the University of Cambridge
Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2024
ib
Paper 1
Created
2026-09-24
Updated
2026-09-24
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Solution
17A
Solution
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17A
A
Givens rotation
Ω
[
p
,
q
]
is the identity except in rows and columns
p
,
q
, where it has the block
(
c
−
s
s
c
)
,
c
=
cos
θ
,
s
=
sin
θ
.
(1)
For
a
=
A
p
j
and
b
=
A
q
j
, choose
c
=
a
2
+
b
2
a
,
s
=
a
2
+
b
2
b
(2)
when
(
a
,
b
)
=
(
0
,
0
)
. Then
(
Ω
[
p
,
q
]
A
)
q
j
=
−
s
a
+
c
b
=
0.
(3)
If both entries vanish, any
angle
works
.
For the given
matrix
,
first
use
Ω
[
1
,
3
]
=
1/
2
0
−
1/
2
0
1
0
1/
2
0
1/
2
.
(4)
It gives
Ω
[
1
,
3
]
A
=
2
0
0
1
3
1
1
0
3
.
(5)
Then use
Ω
[
2
,
3
]
=
1
0
0
0
3
/2
−
1/2
0
1/2
3
/2
.
(6)
Thus
R
=
Ω
[
2
,
3
]
Ω
[
1
,
3
]
A
is
R
=
2
0
0
1
2
0
1
3
/2
3/2
.
(7)
All leading row entries are positive. The resulting
QR decomposition by Givens rotations
is
A
=
QR
,
(8)
where
Q
=
(
Ω
[
2
,
3
]
Ω
[
1
,
3
]
)
T
=
2
/2
0
2
/2
−
2
/4
3
/2
2
/4
−
6
/4
−
1/2
6
/4
(9)
and
R
is the
matrix
above. Since it is
a
product of transposed
rotations
,
Q
is orthogonal.
Ancestors
(9)
Paper 1
ib
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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