For a general Lagrangian,Along an Euler-Lagrange trajectory,so energy is conserved when has no explicit time dependence.
For the given Lagrangian, write . At points where ,The Euler-Lagrange equation is thereforeIn expanded form its left-hand side isThe momentum has fixed magnitude,so this is constant without needing to solve the equation of motion. The Hamiltonian is
The singular Legendre transform of a degree-one velocity Lagrangian applies here: determines only the direction of , not its magnitude, and the velocity Hessian is not invertible. Thus the usual inverse Legendre transform cannot reconstruct the Lagrangian from this Hamiltonian.
Articles by others on the same topic
There are currently no matching articles.