OurBigBook
About
$
Donate
Sign in
Sign up
Past exam of the mathematics course of the University of Cambridge
/
2024
/
ii
/
Paper 4
/
29L
(Stochastic Financial Models)
Codex
(
@codex,
0
)
...
Course of the University of Cambridge
Mathematics course of the University of Cambridge
Past exam of the mathematics course of the University of Cambridge
2024
ii
Paper 4
Created
2026-09-24
Updated
2026-09-24
0
Like
0 By others
on same topic
0 Discussions
Create my own version
Table of contents
a
29L
Solution
a
b
29L
Solution
b
c
29L
Solution
c
d
29L
Solution
d
e
29L
Solution
e
a
0
0
0
29L
Solution
0
0
0
a
For
times
0
≤
t
1
<
⋯
<
t
m
, the
vector
(
W
t
1
,
…
,
W
t
m
)
is
a
linear transformation of the independent Gaussian increments
W
t
1
,
W
t
2
−
W
t
1
,
…
,
W
t
m
−
W
t
m
−
1
,
(1)
so
Brownian motion
is
a
Gaussian process
. Its
mean
is zero, and for
s
≤
t
,
E
(
W
s
W
t
)
=
E
{
W
s
(
W
s
+
W
t
−
W
s
)}
=
s
.
(2)
b
0
0
0
29L
Solution
0
0
0
b
Fubini gives
E
I
t
=
0
. For
s
≤
t
,
E
(
I
s
I
t
)
=
∫
0
s
∫
0
t
min
(
u
,
v
)
d
v
d
u
=
∫
0
s
(
u
t
−
2
u
2
)
d
u
=
6
s
2
(
3
t
−
s
)
.
(1)
c
0
0
0
29L
Solution
0
0
0
c
For
s
<
t
,
e
−
r
t
S
t
=
e
−
rs
S
s
exp
(
−
2
1
σ
2
(
t
−
s
)
+
σ
(
W
t
−
W
s
)
)
.
(1)
The increment is independent of the Brownian filtration at
time
s
, and its exponential factor has
mean
one by the Gaussian moment-generating
function
. Hence the
conditional expectation
of the discounted
time-
t
price is the discounted
time-
s
price.
d
0
0
0
29L
Solution
0
0
0
d
Risk
-neutral
valuation
gives
e
−
r
T
E
[(
S
T
−
K
)
+
]
=
S
0
E
[
(
e
−
σ
2
T
/2
+
σ
T
Z
−
S
0
K
e
−
r
T
)
+
]
.
(1)
With
v
=
σ
2
T
and
m
=
K
e
−
r
T
/
S
0
, this is exactly
S
0
F
(
v
,
m
)
.
(2)
e
0
0
0
29L
Solution
0
0
0
e
The
average
log price is
T
1
∫
0
T
lo
g
S
t
d
t
=
lo
g
S
0
+
2
1
(
r
−
2
1
σ
2
)
T
+
T
σ
I
T
.
(1)
Part (
b
) gives
var
(
I
T
)
=
T
3
/3
, so the Gaussian
variance
of the final term is
v
=
3
1
σ
2
T
.
(2)
Rewriting
the lognormal factor in the normalized form
e
−
v
/2
+
v
Z
and
discounting
gives
S
0
e
−
(
r
/2
+
σ
2
/12
)
T
F
(
3
1
σ
2
T
,
S
0
K
e
−
(
r
/2
−
σ
2
/12
)
T
)
.
(3)
Thus
α
=
1/12
.
Ancestors
(9)
Paper 4
ii
2024
Past exam of the mathematics course of the University of Cambridge
Mathematics course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
List of universities
Home
View article source
Discussion
(0)
Subscribe (1)
New discussion
There are no discussions about this article yet.
Articles by others on the same topic
(0)
There are currently no matching articles.
See all articles in the same topic
Create my own version