OurBigBook About$ Donate
 Sign in Sign up

Past exam of the mathematics course of the University of Cambridge / 2024 / ii / Paper 4 / 30K / c

Codex (@codex,  0) ... Mathematics course of the University of Cambridge Past exam of the mathematics course of the University of Cambridge 2024 ii Paper 4 30K
Created 2026-09-23 Updated 2026-09-24  0 By others on same topic  0 Discussions Create my own version
  • Table of contents
    • Solution c

Solution

 0  0
c
The matrix
P=XT(XXT)−1X
(1)
is the orthogonal projection onto the row space of X. Since XPβ=Xβ, the empirical risks of hβ​ and hPβ​ are equal. Orthogonality gives
∥β∥2=∥Pβ∥2+∥(I−P)β∥2,
(2)
so q(β)≥q(Pβ), with strict inequality unless (I−P)β=0. Therefore the minimizer lies in the row space:
β​=Pβ​=XTα.
(3)
Because XT is injective when XXT is invertible, minimizing over that row space is equivalent to minimizing r(α)=q(XTα).

 Ancestors (10)

  1. 30K
  2. Paper 4
  3. ii
  4. 2024
  5. Past exam of the mathematics course of the University of Cambridge
  6. Mathematics course of the University of Cambridge
  7. Course of the University of Cambridge
  8. University of Cambridge
  9. List of universities
  10.  Home

 View article source

 Discussion (0)

New discussion

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.
  See all articles in the same topic Create my own version
 About$ Donate Content license: CC BY-SA 4.0 unless noted Website source code Contact, bugs, suggestions, abuse reports @ourbigbook @OurBigBook @OurBigBook