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Past exam of the mathematics course of the University of Oxford / 2014 / Prelims / Mathematics I / 6 / a / ii

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Oxford 2014 Prelims Mathematics I 6 a
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ii
The center of a group consists of its elements commuting with every element. First check it is a subgroup. The identity element is central. If a,b∈Z(G) and x∈G, then b−1 commutes with x and
(ab−1)x=a(xb−1)=x(ab−1).
(1)
Thus ab−1∈Z(G), proving closure under the subgroup criterion. Moreover, if z∈Z(G), then xzx−1=z for every x∈G. Hence conjugation fixes the center elementwise, so
xZ(G)x−1=Z(G)(x∈G).​
(2)
Therefore the center of a group is a normal subgroup.

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