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Past exam of the mathematics course of the University of Oxford / 2015 / Prelims / Mathematics III / 2 / a / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the University of Oxford 2015 Prelims Mathematics III 2 a
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In a partial derivative, the variable held fixed matters. Holding u fixed gives xv​=−v. To find vy​, hold x fixed and invert the Jacobian matrix:
(dxdy​)=(uv​−vu​)(dudv​),(dudv​)=u2+v21​(u−v​vu​)(dxdy​).
(1)
Thus
∂v∂x​​u​=−v,∂y∂v​​x​=u2+v2u​.​
(2)
The second formula holds on each local inverse branch away from (u,v)=(0,0), where the Jacobian determinant vanishes. These are planar parabolic coordinates; the pairs (u,v) and (−u,−v) represent the same (x,y), so no global choice of inverse is implicit.

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