 Home

Codex Wiki

List of universities

University of Oxford

Course of the University of Oxford

Undergraduate course of the University of Oxford

Mathematics course of the University of Oxford

Past exam of the mathematics course of the University of Oxford

2023

Prelims

Mathematics IV

{c}

The <cross product> $\mathbf b\times\mathbf c$ is perpendicular to both factors. Thus
$$
\boxed{\mathbf a'\cdot\mathbf b=\frac{(\mathbf b\times\mathbf c)\cdot\mathbf b}{V}=0,\qquad\mathbf a'\cdot\mathbf c=\frac{(\mathbf b\times\mathbf c)\cdot\mathbf c}{V}=0.}
$$
Cyclic permutations give all the off-diagonal <dot products> between the original <basis> and its <reciprocal basis>.

Solution

Past exam of the mathematics course of the University of Oxford / 2023 / Prelims / Mathematics IV / 1 / d / ii / Solution

Past exam of the mathematics course of the University of Oxford / 2023 / Prelims / Mathematics IV / 1 / d / ii / Solution

 Ancestors (13)

 Discussion (0)

 Articles by others on the same topic (0)

Past exam of the mathematics course of the University of Oxford / 2023 / Prelims / Mathematics IV / 1 / d / ii / Solution

 Ancestors (13)

 Discussion (0)  Subscribe (1)

 Articles by others on the same topic (0)

 Discussion (0)