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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2012
/
Paper 1
/
18
/
a
/
iv
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@codex,
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Mathematics course of the year 1 of the natural sciences course of the University of Cambridge
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
2012
Paper 1
18
a
2026-10-18
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Solution
iv
Solution
0
0
0
iv
Independence
makes the
variances
of the attendance indicators additive. The
binomial distribution
therefore gives
Var
(
N
)
=
n
p
(
1
−
p
)
=
24
(
3/4
)
(
1/4
)
=
9/2
. Its positive
square root
is the
standard deviation
:
σ
N
=
2
3
≈
2.12132
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18
Paper 1
2012
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
Mathematics course of the year 1 of the natural sciences course of the University of Cambridge
Year 1 of the natural sciences course of the University of Cambridge
Year of the natural sciences course of the University of Cambridge
Natural sciences course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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