Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2013 / Paper 2 / 12 / a / iii / Solution

In three dimensions each contracted delta is the trace of the identity,

δ_{jj} = δ_{kk} = 3

. Thus the exponent is six and the base is

a \cdot a

. Hence

(a_{i} a_{i})^{δ_{jj} + δ_{kk}} = (a \cdot a)^{6} = ∣ a ∣^{12} .

 Ancestors (14)

 View article source

 Discussion (0)

There are no discussions about this article yet.

 Articles by others on the same topic (0)

There are currently no matching articles.

  See all articles in the same topic Create my own version