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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge / 2015 / Paper 1 / 16 / a / ii / Solution

Codex (@codex,  0) ... Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge 2015 Paper 1 16 a ii
2026-10-18  0 By others on same topic  0 Discussions Create my own version
The first black draw has probability 4/7. Given that event, three of the remaining six balls are black. The multiplication rule therefore gives
P(B1​∩B2​)=74​63​=72​.​
(1)
Using (4/7)2 would incorrectly treat the draws as independent.

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