The product in the integrand simplifies to below its upper endpoint. With the integration by substitution , the limits become and zero and . ThereforeAlthough the tangent function itself is undefined at the upper endpoint, the product has a zero limit there, so its continuous extension, or its improper integral, gives this same result.
To obtain directly from a Riemann sum, divide into equal pieces of width and use right endpoints . The sum isThe integrand is continuous, so the limit of these Riemann sums is its definite integral, namely , agreeing with the antiderivative calculation.
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