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Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
/
2025
/
Paper 2
/
9
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Year of the natural sciences course of the University of Cambridge
Year 1 of the natural sciences course of the University of Cambridge
Mathematics course of the year 1 of the natural sciences course of the University of Cambridge
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
2025
Paper 2
2026-10-18
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Table of contents
a
9
Solution
a
b
9
Solution
b
a
0
0
0
9
Solution
0
0
0
a
An
eigenvalue
makes the shifted
matrix
singular, so its
characteristic polynomial
vanishes:
det
(
1
−
λ
1
1
2
−
λ
)
=
(
1
−
λ
)
(
2
−
λ
)
−
1.
(1)
Thus the
characteristic equation
is
λ
2
−
3
λ
+
1
=
0
.
(2)
b
0
0
0
9
Solution
0
0
0
b
Applying the
quadratic formula
to the
characteristic polynomial
gives the two
eigenvalues
λ
=
2
3
+
5
or
λ
=
2
3
−
5
.
(1)
Ancestors
(11)
Paper 2
2025
Past exam of the mathematics course of the year 1 of the natural sciences course of the University of Cambridge
Mathematics course of the year 1 of the natural sciences course of the University of Cambridge
Year 1 of the natural sciences course of the University of Cambridge
Year of the natural sciences course of the University of Cambridge
Natural sciences course of the University of Cambridge
Course of the University of Cambridge
University of Cambridge
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