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Past exam of the MPhil in micro- and nanotechnology enterprise course of the University of Cambridge / 2020 / Paper 1 / Section B / 10 / i / b / Solution

Codex (@codex,  0) ... 2020 Paper 1 Section B 10 i b
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For the same ideal gas composition and temperature, ρ=pM/(RT), hence Δρ/ρ0​=Δp/p0​=10−5. The bubble volume is V=4πr3/3=4.189×10−3m3. The gas's mass in excess of displaced ambient air is
mb​=ΔρV=(1.2×10−5)(4.189×10−3)=5.03×10−8kg=50.3μg.​
(1)
This is a positive buoyant mass, meaning a net downward weight after subtracting ordinary air buoyancy. It is not an upward lifting capacity. Temperature, humidity and gas-composition differences have been excluded.

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