Past exam of the MPhil in micro- and nanotechnology enterprise course of the University of Cambridge / 2022 / Paper 1 / Section B / 11 / ii / b / Solution

One mole of the overall discharge reaction transfers one mole of electrons. Count both active electrode reactants, including the graphite host:Using the preceding constant-voltage approximation,so the ideal active-material specific energy isThis assumes complete one-electron utilization and the proxy $4.2\mathrm{V}$ throughout discharge. It is not a packaged-cell value or a cathode-only value. A varying equilibrium voltage requires integrating $\int VdQ$; using a maximum voltage as a constant average overestimates the delivered energy.