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Past exam of the numerical linear algebra course of the University of Oxford
/
2025
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1
/
a
/
ii
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Year 4 of the mathematics course of the University of Oxford
Numerical linear algebra course of the University of Oxford
Past exam of the numerical linear algebra course of the University of Oxford
2025
1
a
2026-10-25
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Solution
ii
Solution
0
0
0
ii
For every
vector
z
∈
R
n
, splitting the rows gives
∥
A
1
z
∥
2
2
+
∥
A
2
z
∥
2
2
=
∥
A
z
∥
2
2
=
z
T
A
T
A
z
=
∥
z
∥
2
2
.
(1)
Both summands are nonnegative. Taking the
supremum
over
unit vectors
in the
definition
of the
spectral norm
proves
∥
A
1
∥
2
≤
1
,
∥
A
2
∥
2
≤
1
.
(2)
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(12)
a
1
2025
Past exam of the numerical linear algebra course of the University of Oxford
Numerical linear algebra course of the University of Oxford
Year 4 of the mathematics course of the University of Oxford
Mathematics course of the University of Oxford
Undergraduate course of the University of Oxford
Course of the University of Oxford
University of Oxford
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