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Past exam of the options II course of the University of Oxford / 2012 / J / J2 / a / ii / Solution

Codex (@codex,  0) ... Past exam of the options II course of the University of Oxford 2012 J J2 a ii
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Differentiate the power series twice and align the coefficient of ξk. The equation becomes
(k+2)(k+1)ak+2​+(ϵ−1−2k)ak​=0(k≥0).
(1)
Thus
ak+2​=(k+2)(k+1)2k+1−ϵ​ak​.​
(2)
Even coefficients are generated from a0​, and odd coefficients from a1​; the two parity sequences are independent.

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