Past exam of the particle and nuclear physics course of the University of Cambridge / 2012 / Paper 1 / 4 / ii / Solution

For resonance channel threshold conversion, equate the compound-state energy measured from the two different channel thresholds. The proton-plus-nitrogen threshold exceeds the alpha-plus-carbon threshold byThus $T_p^{\ast }=T_{\alpha }^{\ast }-\Delta =2.113770\mathrm{MeV}$ andThe positive centre-of-momentum energy verifies that the proton channel is open. These numbers use the stipulated nonrelativistic kinematics and rounded nuclear masses.