For a signed measure define its total variation measure byThe value at the empty set is zero. For disjoint measurable sets with union , any finite partition of givesTaking the supremum proves one inequality. In the reverse direction choose, for the first sets, finite partitions approaching their variation values. Combining these partitions and the remaining set givesIf one term is infinite, its partition sums can instead be made arbitrarily large. Letting and proves countable additivity, including infinite values. Thus is a positive measure. This uses only countable additivity of , without assuming a Hahn decomposition.
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