For each , choose an open arc about of arclength , and put . It contains every point used by every empirical measure, whereasThus for all . Let . This is closed and for all . But is irrational, so the weak-star limit is normalized arclength andTherefore the proposed implication is false. Weak-star convergence tests continuous functions and does not assert convergence of the indicator function of an arbitrary closed set.
Articles by others on the same topic
There are currently no matching articles.