Set A=x2−y2 and B=2xy. Direct differentiation givesTheir sum vanishes, proving that u is a harmonic function. More generally the Cauchy-Riemann equations give uxx+uyy=vyx−vxy=0 and vxx+vyy=−uyx+uxy=0; the mixed partial derivatives commute because a holomorphic function is smooth. Since eiz2=e−B(cosA+isinA), a harmonic conjugate and the resulting holomorphic function areThese expressions also verify the Cauchy-Riemann equations directly.
uxx=e−B[(4y2−4x2)sinA+(2−8xy)cosA],uyy=e−B[(4x2−4y2)sinA+(8xy−2)cosA].
v=−e−2xycos(x2−y2)+C,f(z)=−ieiz2+iC,C∈R.
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