Put z=eiθ, so dθ=dz/(iz), cos2θ=(z2+z−2)/2 and cos23θ=(z6+2+z−6)/4. The contour integral isThe enclosed poles are 0 and ±1/2. For the rational function displayed without the prefactor 1/(4i), the residue at zero is −21/8 and the two other residues sum to 27/8. Therefore the residue theorem givesA useful independent check is the Fourier series (5−4cosϕ)−1=31[1+2∑k≥12−kcoskϕ]; only its constant and third Fourier coefficients survive.
4i1∮∣z∣=1z(5z2−2z4−2)z8+2z2+z−4dz.
∫02π5−4cos2θcos23θdθ=4i1(2πi)43=83π.
Ancestors (12)
- b
- 3
- S1
- 2019
- Past exam of the short options paper shared by Parts A and B of the physics course of the University of Oxford
- Short options paper shared by Parts A and B of the physics course of the University of Oxford
- Physics course of the University of Oxford
- Undergraduate course of the University of Oxford
- Course of the University of Oxford
- University of Oxford
- List of universities
- Home
Discussion (0)
New discussionThere are no discussions about this article yet.
Articles by others on the same topic (0)
There are currently no matching articles.