Use the branch cut [−1,1] and the branch of a multivalued function normalized by z2−1∼z. The Laurent series from the preceding solution has z−1 coefficient 3/8. Consequently every sufficiently large positively oriented circle givesAlthough f grows cubically, its other Laurent series terms have zero contour integral. Choosing the opposite branch of a multivalued function reverses the sign; neither the branch of a multivalued function nor the orientation can be omitted from the answer.
∮C∞f(z)dz=43πi.
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