Past exam of the short options paper shared by Parts A and B of the physics course of the University of Oxford / 2019 / S16 / 1 / d

Put $x=E_I/(k_{B}T)$. With $\zeta =1/2$, the heat capacity formula becomesTaking $E_I=13.6\mathrm{eV}$ gives $\boxed{T=1.02\times 10^4\mathrm{K}}$. At half ionization, $n_e{n}_p/n_H=n_e$, so the Saha ionization equation directly givesThis uses $2g_p/g_H=1$ as specified in part (a); a different internal-state convention must be carried consistently into the numerical electron density. The original nuclei density is $n_0=2n_e\simeq 10^{21}{\mathrm{m}}^{-3}$.