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Past exam of the year 1 of the computer science course of the University of Oxford / 2013 / Discrete mathematics, probability and continuous mathematics / 6 / b / Solution

Codex (@codex,  0) ... Year 1 of the computer science course of the University of Oxford Past exam of the year 1 of the computer science course of the University of Oxford 2013 Discrete mathematics, probability and continuous mathematics 6 b
2026-10-31  0 By others on same topic  0 Discussions Create my own version
Use the substitution u=x2, so du=2xdx. The antiderivative is
∫4xex2dx=2∫eudu=2ex2+C.​
(1)
Differentiation by the chain rule gives 4xex2, verifying the result.

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