Select entries having the requested column. The representation invariant ensures that the selected list has length at most one.
def get(i: Int, j: Int): Double = {
  require(0 <= i && i < N && 0 <= j && j < N)
  val entries = rows(i).filter(e => e._1 == j)
  if (entries.isEmpty) 0.0 else entries.head._2
}
Consequently
(1)
This version follows the hint and has time complexity linear in the number of stored entries in row i. An ordered early-exit scan is also possible.

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