Fix one distinguished element of the -element set. Every partition of a set into blocks belongs to exactly one of two cases. If is a block, removing it leaves an -block partition of a set of the other elements, giving possibilities. Otherwise remove from its block; that block remains nonempty, so the result has blocks. Conversely choose any of the such partitions and insert in any one of its blocks. This gives possibilities.
These cases are disjoint and exhaustive, proving the Stirling numbers of the second kind recurrence
Use , for , and for ; these conventions include the boundary cases and .

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