Past exam of the year 1 of the computer science course of the University of Oxford / 2016 / Imperative programming (resit) / 6 / b / Solution

The output becomes BCA, without a newline. Here each method body consists only of super.m; the semicolon ends that definition. The following print("B") or print("C") is a separate statement in the trait body, so it executes during construction.

Creating new D initializes the shared base and then the B and C mixins, printing BC. The subsequent d.m still forwards along C,B,A, but only A.m now prints anything, appending A. Thus it is the placement of the construction-time statements, not a changed Scala trait linearization, that changes the output. ^[ref]