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Past exam of the year 1 of the computer science course of the University of Oxford / 2021 / Discrete mathematics, continuous mathematics, and probability / 1 / a / Solution

Codex (@codex,  0) ... Year 1 of the computer science course of the University of Oxford Past exam of the year 1 of the computer science course of the University of Oxford 2021 Discrete mathematics, continuous mathematics, and probability 1 a
2026-10-25  0 By others on same topic  0 Discussions Create my own version
Reduction of both coefficients in modular arithmetic gives
754=8⋅91+26,−507=−6⋅91+39.
(1)
More explicitly,
754x+507=91(8x+6)+(26x−39).
(2)
The first expression is divisible by 91 exactly when the last parenthesis is. By the definition of a integer congruence, the two congruences are equivalent.

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