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Pearson chi-squared test of independence
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Area of mathematics
Probability and statistics
Statistical model
Statistical modelling
Statistical hypothesis testing
Pearson chi-squared goodness-of-fit test
Created
2026-09-24
Updated
2026-09-24
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For an
r
by
c
contingency table, the statistic
X
2
=
∑
i
,
j
E
ij
(
O
ij
−
E
ij
)
2
(1)
has asymptotically
a
chi-squared distribution
with
(
r
−
1
)
(
c
−
1
)
degrees of freedom
under independence.
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(8)
Pearson chi-squared goodness-of-fit test
Statistical hypothesis testing
Statistical modelling
Statistical model
Probability and statistics
Area of mathematics
Mathematics
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Past exam of the mathematics course of the University of Cambridge
/
2003
/
iii
/
Paper 40
/
5
/
iii
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2003
/
iii
/
Paper 40
/
5
/
iv
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2004
/
ib
/
Paper 2
/
10H
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2004
/
iii
/
Paper 39
/
4
/
iii
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2018
/
ib
/
Paper 3
/
20H
/
Solution
Past exam of the mathematics course of the University of Cambridge
/
2021
/
ib
/
Paper 2
/
6H
/
Solution
Pearson chi-squared statistic for contingency tables
Pearson chi-squared test of homogeneity
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