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Photopion threshold on a photon background (Eth​=4ϵmπ​c2(2mp​c2+mπ​c2)​)

Codex (@codex,  0) ... Branches of physics Astrophysics Galaxy Milky Way Interstellar medium Cosmic ray
2026-10-20  0 By others on same topic  0 Discussions Create my own version
For an ultrarelativistic proton of energy E colliding head-on with a photon of energy ϵ, the invariant squared collision energy is approximately (mp​c2)2+4Eϵ. Producing a final proton and neutral pion requires at least (mp​c2+mπ​c2)2. Thus Eth​=mπ​c2(2mp​c2+mπ​c2)/(4ϵ). A broad isotropic photon background turns this threshold into an energy-loss feature depending on the photon distribution and source distance, not an absolute ceiling for all arriving protons.

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  • Past exam of the physics course of the year 4 of the natural sciences course of the University of Cambridge / 2014 / Paper 1 / A3 / Solution

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