Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / ia / Paper 2 / 4F / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 39 / 2 / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 43 / 2 / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 44 / 5 / a / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 44 / 5 / b / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 44 / 5 / c / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 45 / 3 / ii / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / iii / Paper 47 / 6 / Solution

Past exam of the mathematics course of the University of Cambridge / 2005 / ii / Paper 2 / 5I / Solution

Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 30 / 1 / c / Solution

Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 32 / 6 / b / iii / Solution

Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 34 / 1 / Solution

Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 41 / 3 / Solution

Past exam of the mathematics course of the University of Cambridge / 2006 / iii / Paper 43 / 2 / Solution

{c}
{title2=$\operatorname{Pois}(\lambda)$}
{wiki}

= Poisson random variable
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{synonym}

= Poisson distributed
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{synonym}

= Poisson
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{synonym}

The Poisson distribution with mean lambda assigns mass $e^{-\lambda}\lambda^k/k!$.


Poisson distribution

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 Incoming links: Poisson distribution