Let be a bounded real measurable coefficient on an open set. Nonnegativity of clearly makes its gradient form nonnegative. Conversely, if on a set of positive measure, choose an interior Lebesgue point where . For a nonconstant compactly supported smooth function , set . Change variables and use the Lebesgue differentiation theorem to obtain , a contradiction. Thus the linear operator represented by is monotone exactly when almost everywhere.
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