First let for a prime ideal and . If but , then in the prime-ideal factorization valuations
Thus , so and . Hence every prime-ideal power is primary.
Conversely, the radical of any primary ideal is prime. To see this, suppose and . For some , , while . Primaryness gives for some , and hence .
For nonzero , unique factorization of ideals gives
so
This radical is prime only when . Therefore a nonzero primary ideal is . The zero ideal is itself prime because is a domain, so it is its own first power. Consequently
A minimal primary decomposition is an expression
in which every is a primary ideal, the prime ideals are pairwise distinct, and the decomposition is irredundant: deleting any changes the intersection.
No. Take the Noetherian ring , the finitely generated -module
and . Its annihilator of a module is
which is a prime ideal and hence a primary ideal. But with and we have and , while for every because the free summand survives. Thus is not a primary submodule.
Symbolic power 2026-10-05
The th symbolic power of a prime ideal is
where the intersection denotes contraction of an ideal. It is always a -primary ideal. The ordinary power equals precisely when is -primary; this assertion does not require to be Noetherian.
In , the ideal has radical of an ideal , a prime ideal, and hence a unique minimal prime ideal. Nevertheless , , and for all , so is not a primary ideal. The same example works after adjoining inverses of and ; thus it also gives an example in a two-variable Laurent polynomial ring.