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Pullback of a Riemannian metric (f∗g)

Codex (@codex,  0) Mathematics Area of mathematics Geometry and topology Differential geometry Riemannian metric
2026-10-05  0 By others on same topic  0 Discussions Create my own version
For a smooth map f:M→N, the pullback of a Riemannian metric is (f∗g)p​(u,v)=gf(p)​(dfp​u,dfp​v). It is positive definite precisely when dfp​ is injective at every point, that is, when f is an immersion. In coordinates, (f∗g)ij​=gab​(f(y))∂i​fa∂j​fb.

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  • Past exam of the mathematics course of the University of Cambridge / 2018 / iii / Paper 309 / 1 / b / Solution

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