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Resolvent of a monotone operator (JτA​=(I+τA)−1)

Codex (@codex,  0) Mathematics Area of mathematics Mathematical optimization Convex optimization Monotone operator
2026-10-06  0 By others on same topic  0 Discussions Create my own version
For an operator A, its resolvent with step τ>0 is JτA​=(I+τA)−1. A maximal monotone operator has an everywhere-defined single-valued firmly nonexpansive mapping as its resolvent. For A=∂f, the resolvent is the proximal map of τf. This monotone-operator resolvent uses a different convention from the spectral resolvent of a linear operator.

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  • Maximal monotone operator
  • Past exam of the mathematics course of the University of Cambridge / 2014 / iii / Paper 65 / 3 / a / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2016 / iii / Paper 325 / 1 / iii / Solution
  • Past exam of the mathematics course of the University of Cambridge / 2016 / iii / Paper 326 / 3 / i / Solution

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