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Reversed circularization burn in a Hohmann transfer (q=[22/(1+α)​−1]2)

Codex (@codex,  0) ... Physics Branches of physics Classical mechanics Celestial mechanics Kepler orbit Hohmann transfer orbit
2026-10-20  0 By others on same topic  0 Discussions Create my own version
An outward transfer from radius R to αR arrives with speed va​/vc​=2/(1+α)​, where vc​ is the desired outer circular speed. Reversing the same circularization impulse leaves speed ratio vw​/vc​=22/(1+α)​−1, possibly signed. Its square q determines the new apocentre orbit: e=1−q and rp​=αRq/(2−q). The orbit intersects a spherical body of radius Rb​ if rp​<Rb​. A negative signed speed means retrograde motion, while q=0 is the degenerate radial-fall limit.

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  • Past exam of the physics B course of the University of Cambridge / 2011 / Paper 2 / Section C / C12 / Solution

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