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Shear and pressure force partition in cylinder lubrication (Fws​=2μUJ1​,Fcs​=−2μWJ1​,Fcp​=2μ(W−U)J1​)

Codex (@codex,  0) ... Branches of physics Fluid mechanics Viscous fluid flow Viscous shear torque Torque-free cylinder in a lubrication gap Falling cylinder near a wall
2026-10-14  0 By others on same topic  0 Discussions Create my own version
In the translating-cylinder frame, a wall moves at −U and the nearby cylinder surface at W. With gap d+x2/(2a) and equal outer pressures, lubrication theory gives the displayed forces with J1​=π2a/d​. Wall and cylinder shear forces alone do not balance because the sloping cylinder's pressure force is of the same order. Their complete sum is zero. Pressure exerts no moment about the circular cylinder center, while shear supplies the leading singular rotational resistance.

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  1. Falling cylinder near a wall
  2. Torque-free cylinder in a lubrication gap
  3. Viscous shear torque
  4. Viscous fluid flow
  5. Fluid mechanics
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  • Past exam of the mathematics course of the University of Cambridge / 2012 / iii / Paper 75 / 4 / Solution

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