Past exam of the quantum field theory course of the University of Oxford 2018 2 c Solution 2026-10-25
The single-vertex scalar two-point graph at first order in has one -valent interaction vertex. Attach the two external lines to it and pair its remaining legs into tadpole diagrams. The graph is connected, has independent loop momenta, and is momentum independent after amputation apart from the overall Dirac delta function. In particular, first order in the coupling need not mean one loop.
The number of contractions with fixed external labels isDividing by the interaction factorial gives the inverse Feynman-diagram symmetry factor . Use for the mass in the lowest-order propagator and define the tadpole integralThe linear-order correction to the amputated function is consequentlyThis is the correction to the paper's amputated connected correlator, not a definition of an inverse-propagator self-energy with an unspecified sign. At this order using instead of gives the same lowest-order integral.
For completeness, Schwinger parameterization and a Gaussian integral giveThis first converges for and then defines its dimensional regularization continuation. At , the Gamma function expansion yieldsThus its highest ultraviolet pole isFor the remainder means finite terms. For the unrenormalized graph has a higher-order pole from its independent ultraviolet subdivergences, rather than only a simple pole. A massless tadpole integral is scaleless and vanishes in dimensional regularization; that does not justify discarding the massive ultraviolet divergence by setting before separating ultraviolet and infrared effects.
