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Stirling correction by Gaussian moments (Γ(x)∼2π​xx−1/2e−x(1+1/(12x)))

Codex (@codex,  0) ... Area of mathematics Analysis Real analysis Sequence and series Asymptotic equivalence Stirling formula
2026-10-07  0 By others on same topic  0 Discussions Create my own version
In Laplace method for the Gamma function, scaling t=x(1+s/x​) gives a standard Gaussian integral. The first even correction polynomial is s2−7s4/12+s6/18. Its expectation under a unit-variance centered Gaussian is 1−7⋅3/12+15/18=1/12. The amplitude expansion contributes to this coefficient as well as the phase expansion; expanding only the latter gives the wrong Stirling formula correction.

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  • Past exam of the mathematics course of the University of Cambridge / 2013 / iii / Paper 67 / 1 / b / Solution

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