Let the nearest-neighbour spacing be , so the primitive unit cell has length . Denote the two longitudinal displacements in cell by , with spring within each cell and spring between cells. Hooke's law and Newton's second law giveFor normal modes and , the two amplitudes satisfyIts vanishing determinant gives the alternating-spring chain dispersion relationThe minus sign is the acoustic phonon branch, with and at the origin. The plus sign is the optical phonon branch, with at the origin. For positive springs the acoustic phonon branch rises from zero to at the Brillouin zone edge; the optical phonon branch falls from to . Their long-wavelength limits areThus the leading frequency in the strong-bond limit of the alternating-spring chain is , the internal stretching frequency of a pair with reduced mass .
Let adjacent equal masses be separated by , with alternating strong and weak spring constants and , . The pattern repeats after , even though the masses are identical. Thus the first Brillouin zone isChoose the strong bond inside each two-atom primitive unit cell. With displacement amplitudes , the normal mode equations areThe alternating-spring chain dispersion relation is consequentlyThe lower acoustic phonon branch has in-phase motion within the strongly bound pair and . Its small- slope is the speed of sound,The upper optical phonon branch has opposite motion within each pair, with . Here “optical” names the gapped branch; equal neutral masses need not couple to light through an electric dipole.
In the strong-bond limit of the alternating-spring chain, the pairs act almost as rigid dimers in the low-frequency branch, while their internal stretch gives a high, nearly flat branch:At the zone edge the two frequencies are and , separated by a large forbidden frequency interval. Neighbouring cells are out of phase there. Both branches have horizontal tangents at the edge.

